## Parse an expression

An arithmetical expression consists of 2 numbers and an operator between them, for instance:

`1 + 2`

`1.2 * 3.4`

`-3 / -6`

`-2 - 2`

The operator is one of: `"+"`

, `"-"`

, `"*"`

or `"/"`

.

There may be extra spaces at the beginning, at the end or between the parts.

Create a function `parse(expr)`

that takes an expression and returns an array of 3 items:

- The first number.
- The operator.
- The second number.

For example:

```
let [a, op, b] = parse("1.2 * 3.4");
alert(a); // 1.2
alert(op); // *
alert(b); // 3.4
```

A regexp for a number is: `-?\d+(\.\d+)?`

. We created it in the previous task.

An operator is `[-+*/]`

. The hyphen `-`

goes first in the square brackets, because in the middle it would mean a character range, while we just want a character `-`

.

The slash `/`

should be escaped inside a JavaScript regexp `/.../`

, we???ll do that later.

We need a number, an operator, and then another number. And optional spaces between them.

The full regular expression: `-?\d+(\.\d+)?\s*[-+*/]\s*-?\d+(\.\d+)?`

.

It has 3 parts, with `\s*`

between them:

`-?\d+(\.\d+)?`

??? the first number,`[-+*/]`

??? the operator,`-?\d+(\.\d+)?`

??? the second number.

To make each of these parts a separate element of the result array, let???s enclose them in parentheses: `(-?\d+(\.\d+)?)\s*([-+*/])\s*(-?\d+(\.\d+)?)`

.

In action:

```
let regexp = /(-?\d+(\.\d+)?)\s*([-+*\/])\s*(-?\d+(\.\d+)?)/;
alert( "1.2 + 12".match(regexp) );
```

The result includes:

`result[0] == "1.2 + 12"`

(full match)`result[1] == "1.2"`

(first group`(-?\d+(\.\d+)?)`

??? the first number, including the decimal part)`result[2] == ".2"`

(second group`(\.\d+)?`

??? the first decimal part)`result[3] == "+"`

(third group`([-+*\/])`

??? the operator)`result[4] == "12"`

(forth group`(-?\d+(\.\d+)?)`

??? the second number)`result[5] == undefined`

(fifth group`(\.\d+)?`

??? the last decimal part is absent, so it???s undefined)

We only want the numbers and the operator, without the full match or the decimal parts, so let???s ???clean??? the result a bit.

The full match (the arrays first item) can be removed by shifting the array `result.shift()`

.

Groups that contain decimal parts (number 2 and 4) `(.\d+)`

can be excluded by adding `?:`

to the beginning: `(?:\.\d+)?`

.

The final solution:

```
function parse(expr) {
let regexp = /(-?\d+(?:\.\d+)?)\s*([-+*\/])\s*(-?\d+(?:\.\d+)?)/;
let result = expr.match(regexp);
if (!result) return [];
result.shift();
return result;
}
alert( parse("-1.23 * 3.45") ); // -1.23, *, 3.45
```